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We will first consider a simple implementation of the V model with a jump unravelling for a single bath. We will consider the model that is explicity studied in
The Hamiltonian of this model is a 3 level system given by
\begin{equation}
H = (\nu - \Delta)\ket{2}\bra{2} + \nu \ket{3}\bra{3},,
\end{equation}
where $\nu$ is the energy level and $\Delta$ parameterises the degeneracy between the two levels.
There are two extreme limits in this model; the first corresponding to the Unified master equation which occurs when $\Delta$ is very small, and the the Secular approximation when $\Delta$ is larger.
In the former case we will have two dissipators acting on the system coupled to the Left reservoir
where $\gamma(\omega) = \mathcal{J}(\omega)[n(\omega)+1]$ and $\gamma(-\omega) = \mathcal{J}(\omega)n(\omega)$ are the dissipation rates of the downward and upward channels respectively, $\mathcal{J}(\omega)= a \omega$ is a Ohmic spectral density, and $n(\omega ) = (e^{\beta \omega} - 1)^{-1}$ is the Bose-Einstein distribution.
We will further have the two dissipators coupling to the Right reservoir given by
$$R_{-} = \gamma(\nu)(\ket{1}\bra{2} + \alpha \ket{1}\bra{3}) \quad \text{and} \quad R_{+} = \gamma(-\nu)(\ket{2}\bra{1} + \alpha \ket{3}\bra{1}),,$$
Under the Unified master equation (Eq. 10 in the paper) these clustered noise operators can be rewritten in the Schrodinger picture using a slight change of basis in the following form
Given that we have this in Lindblad form, we can easily write this as an unravelled master equation for quantum jumps, where we associate a jump with either $L_{-}$ or $L_{+}$. It is important to note that these jumps do not distinguish which transition the jump came from i.e ($\ket{1}\bra{2}$ or $\ket{1}\bra{3}$) thus erasing any 'which way' information.
The Secular approximation is valid when the energy difference between the two levels $\Delta$ is large. This ensures that there is now a clear distinction between the energy levels creating which way information. As such the each of the dissipators is split up into seperate dissipators and we obtain
and likewise for the $R$ operators. Therefore under the Secular approximation, there is a clear distinction between the energy levels and which way information is preserved. As such, each of the $L$ operators and $R$ operators can be split into separate dissipators, resulting in a total of four noise operators for the system coupled to each reservoir.